<span id="mktg5"></span>

<i id="mktg5"><meter id="mktg5"></meter></i>

        <label id="mktg5"><meter id="mktg5"></meter></label>
        最新文章專題視頻專題問答1問答10問答100問答1000問答2000關鍵字專題1關鍵字專題50關鍵字專題500關鍵字專題1500TAG最新視頻文章推薦1 推薦3 推薦5 推薦7 推薦9 推薦11 推薦13 推薦15 推薦17 推薦19 推薦21 推薦23 推薦25 推薦27 推薦29 推薦31 推薦33 推薦35 推薦37視頻文章20視頻文章30視頻文章40視頻文章50視頻文章60 視頻文章70視頻文章80視頻文章90視頻文章100視頻文章120視頻文章140 視頻2關鍵字專題關鍵字專題tag2tag3文章專題文章專題2文章索引1文章索引2文章索引3文章索引4文章索引5123456789101112131415文章專題3
        問答文章1 問答文章501 問答文章1001 問答文章1501 問答文章2001 問答文章2501 問答文章3001 問答文章3501 問答文章4001 問答文章4501 問答文章5001 問答文章5501 問答文章6001 問答文章6501 問答文章7001 問答文章7501 問答文章8001 問答文章8501 問答文章9001 問答文章9501
        當前位置: 首頁 - 科技 - 知識百科 - 正文

        CodeforcesRound#273(Div.2)BRandomTeams_html/css

        來源:懂視網 責編:小采 時間:2020-11-27 15:56:32
        文檔

        CodeforcesRound#273(Div.2)BRandomTeams_html/css

        CodeforcesRound#273(Div.2)BRandomTeams_html/css_WEB-ITnose:題目鏈接:Random Teams B. Random Teams time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output n partici
        推薦度:
        導讀CodeforcesRound#273(Div.2)BRandomTeams_html/css_WEB-ITnose:題目鏈接:Random Teams B. Random Teams time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output n partici

        題目鏈接:Random Teams


        B. Random Teams

        time limit per test

        1 second

        memory limit per test

        256 megabytes

        input

        standard input

        output

        standard output

        n participants of the competition were split into m teams in some manner so that each team has at least one participant. After the competition each pair of participants from the same team became friends.

        Your task is to write a program that will find the minimum and the maximum number of pairs of friends that could have formed by the end of the competition.

        Input

        The only line of input contains two integers n and m, separated by a single space (1?≤?m?≤?n?≤?109) ? the number of participants and the number of teams respectively.

        Output

        The only line of the output should contain two integers kmin and kmax ? the minimum possible number of pairs of friends and the maximum possible number of pairs of friends respectively.

        Sample test(s)

        input

        5 1

        output

        10 10

        input

        3 2

        output

        1 1

        input

        6 3

        output

        3 6

        Note

        In the first sample all the participants get into one team, so there will be exactly ten pairs of friends.

        In the second sample at any possible arrangement one team will always have two participants and the other team will always have one participant. Thus, the number of pairs of friends will always be equal to one.

        In the third sample minimum number of newly formed friendships can be achieved if participants were split on teams consisting of 2 people, maximum number can be achieved if participants were split on teams of 1, 1 and 4 people.





        解題思路:n個人,m個隊,只有在一個隊的人可以兩兩成為朋友,問能比完賽后,朋友的對數的最大值和最小值為多少。

        很顯然,最大值的分法是有n-1個隊中只放一個人, 把剩下的人全放到剩下的那個隊。最少的分法是盡可能的均分n個人到m個隊。具體的朋友對數是簡單的組合,k個人兩兩之間的朋友對數為 C(k,2) = k*(k-1)/2 .




        AC代碼:

        #include #include #include #include #include #include #include #include #include #include #include #include using namespace std;#define INF 0x7ffffffflong long n, m, minn, maxn;long long c(long long x){ return (x*(x-1))/2;}int main(){ #ifdef sxk freopen("in.txt","r",stdin); #endif while(scanf("%lld%lld",&n, &m)!=EOF) { long x = n/m; long y = n%m; if(m == 1) minn = c(n); else minn = y*c(x+1) + (m-y)*c(x); maxn = c(n-m+1); printf("%lld %lld\n", minn, maxn); } return 0;}

        聲明:本網頁內容旨在傳播知識,若有侵權等問題請及時與本網聯系,我們將在第一時間刪除處理。TEL:177 7030 7066 E-MAIL:11247931@qq.com

        文檔

        CodeforcesRound#273(Div.2)BRandomTeams_html/css

        CodeforcesRound#273(Div.2)BRandomTeams_html/css_WEB-ITnose:題目鏈接:Random Teams B. Random Teams time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output n partici
        推薦度:
        • 熱門焦點

        最新推薦

        猜你喜歡

        熱門推薦

        專題
        Top
        主站蜘蛛池模板: 99免费在线观看视频| 国产精品免费视频播放器| 亚洲精品偷拍视频免费观看| 亚洲无码一区二区三区| 在线观看免费人成视频色| 亚洲成AV人网址| 亚洲av无码一区二区三区网站| 亚洲精品国产专区91在线| 一个人免费视频在线观看www| 波多野结衣在线免费观看| 亚洲国产成人久久一区久久| 美女羞羞免费视频网站| 亚洲高清无码在线观看| 一级成人生活片免费看| 国产高清免费在线| 免费无码又爽又黄又刺激网站| av无码免费一区二区三区| 亚洲一区免费在线观看| A片在线免费观看| 中文字幕亚洲综合精品一区| 最新黄色免费网站| 亚洲中文字幕AV每天更新| 欧洲美熟女乱又伦免费视频| 亚洲视屏在线观看| 久久国内免费视频| 亚洲成人免费网址| 四虎成人免费网址在线| 免费人成再在线观看网站| 亚洲人成人无码网www电影首页| 无码人妻一区二区三区免费看| 亚洲AV无码专区在线亚| 国产极品美女高潮抽搐免费网站| 一级免费黄色大片| 久久久久亚洲AV无码专区首JN| 好男人视频社区精品免费| 一二三四在线观看免费中文在线观看 | 中文在线观看国语高清免费| 亚洲 自拍 另类小说综合图区| 中文字幕免费在线播放| 久久亚洲精品国产精品| 免费A级毛片av无码|