詭異的mysqllatin1編碼_MySQL

Mysql 的latin1 不等于標準的latin1（iso-8859-1） 和cp1252,比iso-8859-1多了0x80-0x9f字符，比cp1252多了0x81,0x8d,0x8f,0x90,0x9d 一共5個字符。

http://dev.mysql.com/doc/refman/5.0/en/charset-we-sets.html

latin1 is the default character set. MySQL's latin1 is the same as the Windows cp1252 character set. This means it is the same as the official ISO 8859-1 or IANA (Internet Assigned Numbers Authority) latin1, except that IANA latin1 treats the code points between 0x80 and 0x9f as “undefined,” whereas cp1252, and therefore MySQL's latin1, assign characters for those positions. For example, 0x80 is the Euro sign. For the “undefined” entries in cp1252, MySQL translates 0x81 to Unicode 0x0081, 0x8d to 0x008d, 0x8f to 0x008f, 0x90 to 0x0090, and 0x9d to 0x009d.

這樣在Java中，如果使用標準的iso-8859-1或者cp1252解碼可能出現亂碼。
s.getBytes("iso-8859-1") 或者 s.getBytes("cp1252");

寫了一段代碼來解決這個問題
private String convertCharset(String s){
if(s!=null){
try {
int length = s.length();
byte[] buffer = new byte[length];
//0x81 to Unicode 0x0081, 0x8d to 0x008d, 0x8f to 0x008f, 0x90 to 0x0090, and 0x9d to 0x009d.
for(int i=0;i char c = s.charAt(i);
if(c==0x0081){
buffer[i]=(byte)0x81;
}
else if(c==0x008d){
buffer[i]=(byte)0x8d;
}
else if(c==0x008f){
buffer[i]=(byte)0x8f;
}
else if(c==0x0090){
buffer[i]=(byte)0x90;
}
else if(c==0x009d){
buffer[i]=(byte)0x9d;
}
else{
buffer[i] = Character.toString(c).getBytes("cp1252")[0];
}
}
String result = new String(buffer,"utf-8");
return result;
} catch (UnsupportedEncodingException e) {
logger.error("charset convert error", e);
}
}
return null;
}

摘自 小明思考

聲明：本網頁內容旨在傳播知識，若有侵權等問題請及時與本網聯系，我們將在第一時間刪除處理。TEL:177 7030 7066 E-MAIL:11247931@qq.com