ASP.net實現頁面跳轉的方法

主要是使用response的屬性，代碼如下：
代碼如下:
protected void LinkButton1_Click(object sender, EventArgs e)
        {
            string url = "InfoShow.aspx";
            Response.Redirect(url);
        }

protected void LinkButton1_Click(object sender, EventArgs e)
        {
            string url = "InfoShow.aspx";
            Response.Redirect(url);
        }//當然我們可以在頁面跳轉的時候進行參數傳遞，代碼如下：

protected void Menu1_MenuItemClick(object sender, MenuEventArgs e)
       {
           string url, s;
           s = e.Item.Value.ToString();
           url = "InfoRelease.aspx?UserName=" + s.Trim();
           Response.Redirect(url);
       }

 protected void Menu1_MenuItemClick(object sender, MenuEventArgs e)
        {
            string url, s;
            s = e.Item.Value.ToString();
            url = "InfoRelease.aspx?UserName=" + s.Trim();
            Response.Redirect(url);
        }
 
上面是我的一個項目中的代碼所以有item，大家可以根據自己的情況進行設定。

那么既然傳遞了參數，在跳轉的頁面怎樣獲取呢？？？

代碼如下：

代碼如下:
protected void Page_Load(object sender, EventArgs e)
       {
           if (Request["UserName"] != null)
           {
               string s = Request["UserName"].ToString();
    //           form1.Visible = true;
               txtInfoclass.Text = s;
           }
       }

 protected void Page_Load(object sender, EventArgs e)
        {
            if (Request["UserName"] != null)
            {
                string s = Request["UserName"].ToString();
     //           form1.Visible = true;
                txtInfoclass.Text = s;
            }
        }

代碼如下:
protected void Page_Load(object sender, EventArgs e)
       {
           txtAlert.Text = "";
           if (Request["UserName"] != null)
           {
               string s = Request["UserName"].ToString();
    //           form1.Visible = true;
               txtInfoclass.Text = s;
           }
       }

 protected void Page_Load(object sender, EventArgs e)
        {
            txtAlert.Text = "";
            if (Request["UserName"] != null)
            {
                string s = Request["UserName"].ToString();
     //           form1.Visible = true;
                txtInfoclass.Text = s;
            }
        }

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